1896 Missouri gubernatorial election

1896 Missouri gubernatorial election
← 1892 November 3, 1896 1900 →
 
Nominee Lawrence Vest Stephens Robert E. Lewis
Party Democratic Republican
Popular vote 351,062 307,729
Percentage 52.88% 46.35%

County results
Stephens:      40–50%      50–60%      60–70%      70–80%      80–90%
Lewis:      40–50%      50-60%      60-70%      70-80%

Governor before election

William J. Stone
Democratic

Elected Governor

Lawrence Vest Stephens
Democratic

The 1896 Missouri gubernatorial election was held on November 3, 1896 and resulted in a victory for the Democratic nominee, State Treasurer of Missouri Lawrence Vest Stephens, over the Republican candidate Robert E. Lewis, Prohibition candidate Herman Preston Faris, National Democratic candidate J. McDowell Trimble and Socialist Labor candidate Louis C. Fry.

Results

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1896 gubernatorial election, Missouri[1]
Party Candidate Votes % ±%
Democratic Lawrence Vest Stephens 351,062 52.88 +2.90
Republican Robert E. Lewis 307,729 46.35 +2.85
Prohibition Herman Preston Faris 2,588 0.39 −0.24
National Democratic J. McDowell Trimble 1,809 0.27 +0.27
Socialist Labor Louis C. Fry 757 0.11 +0.11
Majority 43,333 6.53 +1.05
Turnout 663,945 24.78
Democratic hold Swing

References

[edit]
  1. ^ "Our Campaigns - MO Governor Race - Nov 03, 1896".